Jaringan Komputer

Menghitung Alamat IP Address

Hitunglah jumlah Network dan Host yang akan

terbentuk dari alamat IP Address dibawah ini:

1. 192.168.10.1/30

2. 172.168.10.1/16

3. 172.168.10./22

4. 10.168.5.1/8

5. 10.168.5.1/17

Jawab

Rumus : Network : 2n, Host : 2h -2 atau Host = /n-32

1 . IP Address 192.168.10.1/30 ( Class C )

Network : 11111111. 11111111. 11111111. 11111100 (255.255.255.252) = 2 akar 6 = 64 Network

Host : 32-30 = 2

                : 2 akar 2 = 4-2 = 2 host

2. IP Address 172.168.10.1/16 ( Class B )

Network : 11111111. 11111111. 00000000. 00000000 (255.255.0.0) = 2 akar 0 = 1 Network

Host : 32-16 = 16

                : 2 akar 16 = 65.536 – 2 = 65.534 Host

3. IP Address 172.168.10./22 ( Class B )

Network : 11111111. 11111111. 11111100. 00000000 (255.255.252.0) = 2 akar 6 = 64 Network

Host : 32-22 = 10

                : 2 akar 10 = 1024 – 2 = 1022 Host

4. IP Address 10.168.5.1/8 ( Class A )

Network : 11111111. 00000000. 00000000. 00000000 (255.0.0.0) = 2 akar 0 = 1 Network

Host : 32-8 = 24

                : 2 akar 24 = 16.777.216 – 2 = 16.777.214 Host

5. IP Address 10.168.5.1/17 ( Class A )

Netwok : 11111111. 11111111. 10000000. 00000000 (255.255.128.0)= 2 akar 17 = 131.072 Network

Host : 32-17 = 15

               : 2 akar 15 = 32.768 – 2 = 32.766 Host

Link Pembelajaran: https://youtu.be/YzW8vgs_vUQ